題目連結 : Reverse Integer – LeetCode
Python
#7. Reverse Integer 字串反轉
class Solution:
def reverse(self, x: int) -> int:
if x < 0:
a = str(x)[:0:-1]
b = int(a)
b = b * (-1)
else:
a = str(x)[::-1]
b = int(a)
if b > (2**31-1) or b < (-2**31 - 1):
return 0
else:
return b Python
#7. Reverse Integer 純數字運算
class Solution:
def reverse(self, x: int) -> int:
INT_MAX = 2**31 - 1
INT_MIN = -2**31
reversed_number = 0
sign = 1 if x > 0 else -1
x = abs(x)
while x != 0:
digit = x % 10
if reversed_number * 10 + digit > INT_MAX:
return 0 # 檢查是否溢位
reversed_number = reversed_number * 10 + digit
x = x // 10
return reversed_number*sign